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Optically active 2-iodobutane on treatment with sodium iodide in acetone gives a product which does not show optical activity. Explain. |
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Answer» Solution :Optically ACTIVE 2-iodobutane DISSOCIATED to form iodide ion and the carbocation. The iodide ion then attacks the flat carbocation from either side resulting in a mixture of two ENANTIOMERIC products in equal amounts, which CONSTITUTES a RACEMIC mixture which does not show optical activity. |
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