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Order of base strength of the compoundsCH2 NH2□□(a) IV(c) II > III>IV>I(b) III> Il > IV >,I(d) II> IH> I> IV D>II>I > III |
Answer» <p>option B is correct.</p><p>strong acid forms weaker base </p><p>and COOH is stronger acid than Ph-OH , so its conjugate base will be Ph-O- > COO- </p> <p>This is due to lone pair on the nitrogen and extra -ve charge. </p><p>so iii> ii</p> <p>but due to less Electronegativity C with -ve charge is a better donor</p> <p>then may be its an exception.. you can't do much but accepting the fact </p> | |