1.

Organic compound with molecular formula C_(3)H_(6)O has two isomers (A) and (B). (A) on heating with NaOH in I_(2) forms a yellow precipitate while (B) does not. Identify the isomers A and B and explain the reactions.

Answer»

Solution :TWO POSSIBLE isomers of `C_(3)H_(6)O` are
`underset("acetone")underset((A))(CH_(3)COCH_(3))andunderset("PROPANAL")underset((B))(CH_(3)CH_(2)CHO)`
`underset("Acetone")underset((A))(CH_(3)COCH_(3))underset("Iodo form reaction")overset(I_(2)//NaOHDelta)tounderset("acetate")underset("Sodium")(CH_(3)COONa)+underset("Yellow ppt")underset("Iodoform")(CHI_(3))`
`underset("Proponal")underset((B))(CH_(3)CH_(2)CHO)underset(Delta)overset(I_(2)//NaOH)to"No ppt of "CHI_(3)`
Acetone answer Iodo form test whereas proponal does not.


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