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| 1. |
Out of C and CO, which is a better reducing agent for ZnO? |
| Answer» SOLUTION :Refer to Ellingham diagram FIG. 6.1. The standard free energy of FORMATION `(triangle_(f)G^(0))` of CO from C becomes lower above 1223 K and that of `CO_(2)` from C becomes lower above 1323 K than `triangle_(f)G^(0)" of "ZnO`. Therefore, above these temperatures, C can reduce ZnO to Zn. However, `triangle_(f)G^(0)" of "CO_(2)` from CO is always higher than that of ZnO. Therefore, CO cannot reduce ZnO to Zn even at higher temperature (AROUND 1673 K). Thus, out of C and CO, C is a better reducing agent. | |