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| 1. |
Out of HCl and NaCl, which do you expect will have greater value for wedge_(m)^(@) and why? |
| Answer» Solution :HCL will have gerater VALUE for `wedge_(m)^(@)` because `H^(+)` ions are smaller than `Na^(+)` ions. Consequently, `H^(+)` ions will have GREATER ionic mobility and hence ionic CONDUCTANCE than `Na^(+)` ions. | |