1.

Oxidation number of carbon is correctly given for

Answer»

`{:("Compound","O.No."),(HN-= C , +2):}`
`{:("Compound","O.No."),(H-C-=N , +4):}`
`{:("Compound","O.No."),(C C I_4, +4):}`
`{:("Compound","O.No."),(C_6H_(12) O_6, 0):}`

Solution :InJ+HNCit is+2, in `C C I_4`it is+4and in`C_6H_(12)O_6` it ISZERO


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