1.

Oxidation number of sulphur in sulphuryl chloride is

Answer»

`+4`
`+6`
`+2`
`+3`

Solution :Sulphuryl chloride is `SO_(2)Cl_(2)`
`S + 2O + 2Cl=` zero
`therefore x + 2(-2) + 2(-1)=0`
`therefore x-4 -2=0`
`therefore x-6=0, therefore x=+6`


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