Oxidation number ofnitrogen in (NH_4)_2SO_4 is – InterviewSolution

1.	Oxidation number ofnitrogen in (NH_4)_2SO_4 is
Answer» -1/3 -1 +l -3 Solution :(d) `(NH_4)_2,SO_4`, is SPLIT into IONS. `NH_(4)^(+)`. Let O.N. of N be x then, `1 XX (x) + 4 xx (+1)=1, therefore = -3`

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