1.

Oxidation states of P in H_(4)P_(2)O_(5), H_(4)P_(2)O_(6) and H_(4)P_(2_)O_(7), respectively are

Answer»

<P>`+3,+5` and +4
`+5,+3` and +4
`+5,+4` and +3
`+3,+4` and `+5`

Solution :Oxidation state of H is `+1` and that of O is `-2`.
LET the oxidation state of P in the GIVEN compounds is x.
In `H_(4)P_(2)O_(5)`
`(+1)xx4+2xx x+(-2)xx5=0`
`4+2X - 10 = 0`
`2x = 6`
`:. x = +3`
In `H_(4)P_(2)O_(6)`
`(+1) xx4+2xx x + (-2)xx6=0`
`4+2x-12=0`
`2x=8`
`:. x = +4`
In `H_(4)P_(2)O_(7)`
`(+1)xx4+2xx x + (-2)xx7=0`
`4+2x-14=0`
`2x=10`
`:. x = +5`
Thus the oxidation states of `P` in `H_(4)P_(2)O_(5)`. `H_(4)P_(2)O_(6)` and `H_(4)P_(2)O_(7)` are `+3,+4` and `+5` respectively.


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