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Oxygen gas weighing `128 g` is expanded form `1atm` to `0.25 atm` at `30^(@)C`. Calculate entropy change, assuming the gas to be ideal. |
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Answer» `n = (W)/("Molecular weight") = (128)/(32) = 4` `DeltaS = 2.303 nR log_(10) ((P_(1))/(P_(2)))` `= 2.303 xx 4xx 8.314 log_(10) ((1)/(0.25))` `= 46.10 J K^(-1)` |
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