InterviewSolution
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InterviewSolution
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Oxygen is filled in a closed metal jar of volume `1.0xx10^(-3)m^(3)` at a pressure of `1.5xx10^(5)Pa.` and temperature 400K.The jar has a small leak in it. The atmospheric pressure is `1.0xx10^(5)`Pa and the atmospheric temperature is 300K. Find the mass of the gas that leaks out by time the pressure and the temperature inside the jar equlise with the surrounding. |
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Answer» Given ` (V_1)=(1 xx (10^-3)(m^3))` ` P_1= (1.5 xx (10^5)Pa)` ` T_1= 400K` We know ` (P_1)(V_1)= (n_1)(RT_1)` ` rArr n_1 = ((P_1)(V_1)/RT_1)` ` =(1.5 xx (10^5)xx 1 xx (10^-3)/(8.3 xx 400))` ` rArr (m_1) = (1.5 xx M/8.3 xx 4) = (1.5 xx 32/ 4 xx 8.3)` ` = 1.457 ~~1.446` ` Again, (P_2)= 1 xx (10^5)Pa,` ` V_2 = 1 xx (10^-3)(m^3)` ` T_2 = 300K` We know, ` (P_2)(V_2)= (n_2)RT_2` ` rArr (n_2)= ((P_2)(V_2)/(RT_2)) = (10^5 xx (10^-3)/ (8.3 xx 300))` ` = (1/3 xx 8.3)= 0.040` ` rArr m_2= 0.04 xx 32 = 1.285` ` Delta m = (m_1-(m_2))=1.446 -1.285` ` = 0.1608 g ~~ 0.16g.` |
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