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Oxygen is present in a one-litre flask at a pressure of 7.6 xx 10^(-10) mm Hg. Calculate the number of oxygen molecules in the flask at 0^(C). |
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Answer» <P> SOLUTION :`p = 7.7 XX 10^(-10)` ATM`= 0.01 xx 10^(-10)` atm (760 mm = 1 atm) `T = (0+273) = 273 K` We have, pV = nRT `0.01 xx 10^(-10) xx 1 = n xx 0.0821 xx 273, therefore n = (10^(-12))/(0.0821 xx 273)` `therefore` no. of oxygen molecules = mole `xx` Av. const. `= (10^(-12))/(0.0821 xx 273) xx 6.022 xx 10^(23)` `= 2.68 xx 10^(10)`. |
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