1.

P_(2)H_(4) can be romoved from phosphine containing traces of it

Answer»

by passing impure `PH_(3)` gas through a freezing mixture
by passing the impure `PH_(3)` gas through HI and then its treatment with KOH (aq)
by both (a) and (B)
by none of these

Solution :Both the methods (a) and (b) can used.
When passed through freezing miture the `P_(2)H_(4)` present condenses and pure `PH_(3)` is OBTAINED.
When passed through `HI, PH_(3)` is obsorbed FORMING `PH_(4)I.PH_(4)I` when treated with KOH(aq) yields pure phosphine.
`PH_(3)+HI to PH_(4)I`
`PH_(4)I+KOH(aq) to KI+H_(2)O+PH_(3) uparrow`


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