1.

p=2a-3b,q=a-2b+c and r=-3a+b+2c, where a,b,c being non-coplanar vectors, then the vector -2a+3b-c is equal toA. `p-4q`B. `(-7q+r)/(5)`C. `2p-3q+r`D. `4p-2r`

Answer» Correct Answer - B
Let `-2a+3b-c=xp+yq+zr`
`implies-2a+3b-c=(2x+y-3z)a+(-3x-2y+z)b+(y+2z)c`
`therefore 2x+y-3z=-2,-3x-2y+z=3`
and `y+2z=-1`
On solving these we get `x=0,y=-(7)/(5),z=(1)/(5)`
`therefore-2a+3b-c=((-7q+r))/(5)`
trick check alternates one-by-ne
ie.., (a) `p-4q=-2a+5b-4c`
(b) `(-7q+r)/(5)=-2a+3b-c`


Discussion

No Comment Found

Related InterviewSolutions