InterviewSolution
Saved Bookmarks
| 1. |
p=2a-3b,q=a-2b+c and r=-3a+b+2c, where a,b,c being non-coplanar vectors, then the vector -2a+3b-c is equal toA. `p-4q`B. `(-7q+r)/(5)`C. `2p-3q+r`D. `4p-2r` |
|
Answer» Correct Answer - B Let `-2a+3b-c=xp+yq+zr` `implies-2a+3b-c=(2x+y-3z)a+(-3x-2y+z)b+(y+2z)c` `therefore 2x+y-3z=-2,-3x-2y+z=3` and `y+2z=-1` On solving these we get `x=0,y=-(7)/(5),z=(1)/(5)` `therefore-2a+3b-c=((-7q+r))/(5)` trick check alternates one-by-ne ie.., (a) `p-4q=-2a+5b-4c` (b) `(-7q+r)/(5)=-2a+3b-c` |
|