1.

P_4O_(6) reacts with water according to equation P_4O_6 + 6H_2O to 4H_3PO_3 . Calculate the volume of 0.1 M NaOH solution required to neutralise the acid formed by dissolving 1.1 g of P_4O_6 in H_2O.

Answer»

SOLUTION :
No. of moles in `P_4O_6=(1.1)/(220)`
1 MOL `P_4O_6` requires = 8 mol NAOH
`(1.1)/(220)` mol `P_4O_6` required = `8 XX (1.1)/(220)` mol NaOH
`=(8.8)/(220) =0.04 mol` NaOH
Molarity of NaOH solution is 0.1 M
0.1 mol of NaOH is present in =1 litre
0.04 mol NaOH is present in `=(1)/(0.1) xx 0.04 `litre = 400 mL


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