P(-5,-3), Q(-4,-6), R(2,-3) and S (1,2) are the vertices of a quadrilateral PQRS, find its area

P(-5,-3), Q(-4,-6), R(2,-3) and S (1,2) are the vertices of a quadrila

1.	P(-5,-3), Q(-4,-6), R(2,-3) and S (1,2) are the vertices of a quadrilateral PQRS, find its area
Answer» Area of `/_PQR` `=1/2(x1(y2-y3)+x2(y3+y1)+x3(y1-y2)` `=1/2(-5(-6+3)+(-4)(-3+3)+2((-3)+6)` `=1/2(+15+0+6)` `=21/2unit^2` Area of `/_PQR` `=1/2(-5(-3-2)+(2)(2+3)+1((-3)+3)` `=1/2(25+10+0)` `=35/2 unit^2` Area of quad.=Area of `/_PQR`+Area of `/_PRS` `=21/2+35/2` `=56/2` `=28Unit^2`

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