InterviewSolution
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InterviewSolution
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P speaks truth in 70% of the cases and Q in 80% of the cases. In what percent of the cases they are likely to agree in the same fact ? Do you think, when the agree, means both are speaking truth. |
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Answer» Here, probability of `P` speaking truth, `P(T) = 70% = 7/10` `:.` probability of `P` speaking lie, `P(L) = 1- 7/10 = 3/10` Probability of `Q` speaking truth, `Q(T) = 80% = 4/5` `:.` probability of `Q` speaking lie, `Q(L) = 1- 4/5 = 1/5` Probability of both `P` and `Q` agree in same fact `P(S) = P(T)nnQ(T) +P(L)nnQ(L)` As, all these events are indepependent event, `:. P(S) = P(T)Q(T)+P(L)Q(L)` `P(S) = 7/10**4/5+3/10**1/5 = 28/50+3/50 = 31/50` So, percentage of both of them agree on same fact `= 31/50**100 = 62%` Also, we can clearly see that when both of them agree, they also speak lie and probability of that is `3/50`. |
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