P(x)=x⁴+2x³-3x²-x-1,q(x)=x-2

1.	P(x)=x⁴+2x³-3x²-x-1,q(x)=x-2
Answer» Answer: 5 Step-by-step explanation: zeroes of the polynomial is 2, p(2)= (2)4 + (2)(2)3 - (3)(2)2 - (2) - 1 = 8 + 12 - 12 - 2 - 1 = 8 - 3 = 5\\.. HOPE its helpfull... and plz mark me brainliest<3

Answer»

Answer:

Step-by-step explanation:

zeroes of the polynomial is 2,

p(2)= (2)4 + (2)(2)3 - (3)(2)2 - (2) - 1

= 8 + 12 - 12 - 2 - 1

= 8 - 3 = 5\\..

HOPE its helpfull... and plz mark me brainliest<3

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P(x)=x⁴+2x³-3x²-x-1,q(x)=x-2

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