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P(y)= 2y² - 2y + 5 Find = p(0), p(1) , p(-1)​

Answer» P(0)=2×(0)^2-2×0+5 =0-0+5 =5p(1)=2×(1)^2-2(1)+5 =2-2+5 =5p(-1)=2×(-1)^2-2×(-1)+5 =2+2+5 =9Hope this HELPFUL to you


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