1.

Paragraph : A particle vibrates in S.H.M. along a straight line. Its velocity is 4 cm/s when its displacement is 3 cm and velocity is 3 cm/s when displacement is 4 cm. The amplitude of SHM is :

Answer»

5 cm
10 cm
7 cm
9 cm.

Solution :`l=SQRT((u_(1)^(2)n_(2)^(2)-v_(2)^(2)n_(1)^(2))/(u_(1)^(2)-v_(1)^(2)))=sqrt(16xx4^(2)-9xx3^(2))/(16-9)`
`=5` cm
Correct choice is ( c ).


Discussion

No Comment Found

Related InterviewSolutions