1.

Paragraph : A particle vibrates in S.H.M. along a straight line. Its velocity is 4 cm/s when its displacement is 3 cm and velocity is 3 cm/s when displacement is 4 cm. The maximum value of acceleration is :

Answer»

`2" cm"//"s"^(2)`
`3" cm"//"s"^(2)`
`4" cm"//"s"^(2)`
`5" cm"//"s"^(2)`.

Solution :`U_("MAX")=OMEGA^(2)r=((2pi)/(T))^(2)XX r=((2pi)/(2pi))^(2)xx5`
`=5" cm"//"s"^(2)`
So correct CHOICE is (d).


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