Paragraph : A particle vibrates in S.H.M. along a straight line. Its velocity is 4 cm/s when its displacement is 3 cm and velocity is 3 cm/s when displacement is 4 cm. The displacement of an object attached to a spring and executing simple harmonic motion is given by x=2xx10^(-2)cos pi t metres. The time at which the maximum speed first occurs is :

Paragraph : A particle vibrates in S.H.M. along a straight line. Its v

1.	Paragraph : A particle vibrates in S.H.M. along a straight line. Its velocity is 4 cm/s when its displacement is 3 cm and velocity is 3 cm/s when displacement is 4 cm. The displacement of an object attached to a spring and executing simple harmonic motion is given by x=2xx10^(-2)cos pi t metres. The time at which the maximum speed first occurs is :
Answer» 0.75 s 0.125 s 0.25 s 0.5 s Solution :`x=2xx10^(-2)cos pi t`. Comparing it with standard from `x=r cos omegat`. We have `omega=piimplies(2pi)/(T)=pi` `IMPLIES""T=2` second Now in time `t=(T)/(4)` the particle GOES from extreme POSITION to MEAN position where K.E. becomes maximum. `:.""t=(2)/(4)=0.5` So, correct CHOICE is (d).

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