Parallelos (Figure 5.24)Fig. 5.244. Prove that quadrilateral formed by theintersection of angle bisectors of allangles of a parallelogram is a rectangle.

Parallelos (Figure 5.24)Fig. 5.244. Prove that quadrilateral formed

1.	Parallelos (Figure 5.24)Fig. 5.244. Prove that quadrilateral formed by theintersection of angle bisectors of allangles of a parallelogram is a rectangle.
Answer» FIGURE GIVENStep-by-step explanation:GIVEN : ABCD a parallelogramTo PROVE : PQRS is a RECTANGLE DC∣∣AB and DA is a traversal ∴∠A+∠D=180 0 21 ∠A+ 21 ∠D=90 0 ⇒∠SAD+∠SDA=90 0 ∴∠ASD=90 0 ∴ By concept of vertical angles∠ASD=∠PSR=90 0 Simillarly we will get∠PQR=∠QPS=∠QRS=90 0 ∴PQRS is a rectangle

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Parallelos (Figure 5.24)Fig. 5.244. Prove that quadrilateral formed by theintersection of angle bisectors of allangles of a parallelogram is a rectangle.​

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Parallelos (Figure 5.24)Fig. 5.244. Prove that quadrilateral formed by theintersection of angle bisectors of allangles of a parallelogram is a rectangle.