1.

Particles are released from rest A and side down the smooth surface of hight h to a conveyor B. The correct angular veleocity `omega` of the coneyor pulley of readius r to prevent any siding on the beit as the particles transfer to the conveyou is A. `sqrt(2gh)`B. `(2gh)/(r)`C. `sqrt(2gh)/(r)`D. `(2gh^(2))/(r^(2))`

Answer» (c) First of all, we have to calculate the velocity of particles at the point B.
`:.` Loss in PE =gain in KE or mgh `=(1)/(2)mmv^(2)`
`:.` To Prevent sliding , `v=r_(omega)`
`:.` `omega=(v)/(r)=sqrt(2gh)/(r)`


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