InterviewSolution
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InterviewSolution
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particles of masses 2M m and M are resectively at points A , B and C with ` AB = (1)/(2) (BC)` m is much - much smaller than M and at time ` t=0` they are all at rest as given in figure . As subsequent times before any collision takes palce . A. m will remain at restB. m will move towards MC. m will move towards 2MD. m will have oscillatory motion |
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Answer» Correct Answer - C Force on B due to `A=F_(BA)=(G(Mm))/((AB)^(2))` towards BA force on B due to `C=F_(BC)=(GMm)/((BC)^(2))` towards BC As `(BC)=2AB` `rArr F_(BC)=(GMm)/((2AB)^(2))=(GMm)/(4(AB)^(2)) lt F_(BA)` Hence, m will move towards BA(i.e., 2M) |
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