Passage - II : Sulphur forms hexahalides, tetrahalides, dihalides and monohalides, sulphur forms only hexa fluorides but not hexachlorides, hexa bromides and hexaiodides. Sulphur halides tend to hydrolyse easily. Sulphur hexa fluorides is an exception. Of the oxohalides, the most important are those of sulphur especially sulphur dichloride oxide (Thionyl chloride) SOCl_(2) and sulphurdichloride dioxide (Sulphuryl chloride) SO_(2)Cl_(2) these are also hydrolyse in water SF_(6) do not hydrolyse water because

Passage - II : Sulphur forms hexahalides, tetrahalides, dihalides and

1.	Passage - II : Sulphur forms hexahalides, tetrahalides, dihalides and monohalides, sulphur forms only hexa fluorides but not hexachlorides, hexa bromides and hexaiodides. Sulphur halides tend to hydrolyse easily. Sulphur hexa fluorides is an exception. Of the oxohalides, the most important are those of sulphur especially sulphur dichloride oxide (Thionyl chloride) SOCl_(2) and sulphurdichloride dioxide (Sulphuryl chloride) SO_(2)Cl_(2) these are also hydrolyse in water SF_(6) do not hydrolyse water because
Answer» Due to STRONG S-F bonds which cannot be broken EASILY Because of STERIC hinderance of six fluorine atoms surrounding sulphur `H_(2)O` molecules can not approach sulphur Due to double BOND CHARACTER of 'S-F' bonds because of back bonding All the above Solution :Because of steric hinderance of six fluorine atoms surrounding sulphur `H_(2)O` molecules can not approach sulphur.