1.

Passage - VI : Industrially sulphuric acid is produced by the following steps: Stage I : S+O_(2) overset(Delta)to SO_(2) Stage II : 2SO_(2) +O_(2) overset(V_(2)O_(5))to 2SO_(3) Stage III : SO_(3)+H_(2)O to H_(2)SO_(4) Since the reaction between SO_(3) and H_(2)O is violent, SO_(3) is passed into 98% H_(2)SO_(4) to produce oleum (H_(2)S_(2)O_(7)) H_(2)SO_(4)+PCl_(5) to (X) overset(H_(2)O)totwo strong acids where 'x' is

Answer»

`SO_(2)Cl_(2)`
SOCl
`ClSO_(3)H`
`POCl_(3)`

SOLUTION :`SO_(2)Cl_(2)+2H_(2)O to 2HCl +H_(2)SO_(4)`


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