Passage XI) The differential equation of a particle undergoing SHM is given by `a(d^(2)x)/(dt^(2))`+bx = 0. The particle starts from the extreme position. The ratio of the maximum acceleration to the maximum velocity of the particle isA. b/aB. a/bC. `sqrt(a/b)`D. `sqrt(b/a)`

Passage XI) The differential equation of a particle undergoing SHM is

1.	Passage XI) The differential equation of a particle undergoing SHM is given by `a(d^(2)x)/(dt^(2))`+bx = 0. The particle starts from the extreme position. The ratio of the maximum acceleration to the maximum velocity of the particle isA. b/aB. a/bC. `sqrt(a/b)`D. `sqrt(b/a)`
Answer» Correct Answer - D

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Passage XI) The differential equation of a particle undergoing SHM is given by `a(d^(2)x)/(dt^(2))`+bx = 0. The particle starts from the extreme position. The ratio of the maximum acceleration to the maximum velocity of the particle isA. b/aB. a/bC. `sqrt(a/b)`D. `sqrt(b/a)`

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