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PassageII We have two parallel plate capacitors P and Q having same capacitance C_(0). P is connected to a battery of potential difference V and it remains connected to the battery even after the charging is over. Q is also connected to a battery of the same potential difference V but after the charging gets over, it is disconnected from the battery. Answer the following questions: Charge stored in Q, when a dielectric slab is inserted in between the plates

Answer»

INCREASES
decreases
remains same
first increases and after some time becomes same as before

Solution :In the GIVEN passage we should known that potential DIFFERENCE between the plates of P remains constant whereas charge stored in Q will remain constant. All answer are to be OBTAINED keeping these things in MIND.


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