patient a a and patient b have to visit the doctor every 8 days and 10

1.	patient a a and patient b have to visit the doctor every 8 days and 10 days respectively after how many days will both the patients need the doctor on the same day
Answer» Answer: we need to find the LCM of 8 and 10 days in this case factors of 8=2x2x2 factors of 10=2×5 LCM is the product (MULTIPLICATION) of all factors hence, LCM(8,10)= 2x2x2x5=8x5=40 They will need the DOCTOR on the same day after 40 days. PLEASE MARK AS BRAINLIEST! THIS IS YOUR DETAILED ANSWER!

patient a a and patient b have to visit the doctor every 8 days and 10 days respectively after how many days will both the patients need the doctor on the same day

Answer»

Answer:

we need to find the LCM of 8 and 10 days in this case

factors of 8=2x2x2

factors of 10=2×5

LCM is the product (MULTIPLICATION) of all factors

hence, LCM(8,10)= 2x2x2x5=8x5=40

They will need the DOCTOR on the same day after 40 days.

PLEASE MARK AS BRAINLIEST! THIS IS YOUR DETAILED ANSWER!