1.

Pb//PbSO_(4)_((s)), SO_(4(aq))^(-2) Pb_((s))+SO_(4)^(-2) hArr PbSO_(4(s))+ ?

Answer»

`E^(-)`
`3E^(-)`
`2E^(-)`
no electron

Solution :`(Pb_((s)) to PB^(++)+2e^(-))+SO_(4)^(--) to PbSO_4+2e^(-)`


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