1.

PC,(g)PCI,(g)+C2(9)In above reaction, at equilibrium condition molefraction of PC!, is 0.4 and mole fraction of Cl, is 0.3Then find out mole fraction of PCl,(A) 0.3(C) 0.45(B) 0.7(D) 0.6

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my answer is also this but in answer key option showing me option c



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