1.

PCl_(5) in solid state exists as PCl_(4)^(+) and PCl_(6)^(-) and also in some solvents it undergoes dissociation as 2PCl_(5) hArr PCl_(4)^(+) +PCl_(6)^(-) The geometry and hydridisation of PCl_(4)^(+) is

Answer»

Tetrahderal , `sp^3`
OCTAHEDRAL , `sp^(3) d^(2)`
LINEAR , sp
Angular , `sp^2`

Solution :`[PCl_4]^(+)` - No of HYBRID orbitals `=1/2 [5+4-1]=4`


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