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Peak voltage of a carrier is 8kV, each sideband has an amplitude of 800V. Find its modulation index?(a) 0.28(b) 0.09(c) 0.02(d) 0.08I had been asked this question during an internship interview.My question is from Methods of Reducing Distortion in division Amplitude Modulation of Analog Communications

Answer»

The correct answer is (c) 0.02

To elaborate: (mPc)/2 = Psb, wherem = Modulation Index, Pc = Carrier POWER and,

Psb = Power of each sideband

THEREFORE, (mVc ^2)/2 = Vsb 2^2 (Vc= 8000 V, and Vsb = 800)

Therefore, m = (800^2 X 2) / 8000^2 = 0.02.


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