InterviewSolution
| 1. |
pelimentalyxluceaobservations.yourlength is held 25 cm away from a converging lens of focallene.An object 5 cm incm. Draw the ray diagramand find the position, size and the nature of the10image formed.11. A concave lens of focal length 15 cm forme |
|
Answer» Given, height of object = 5cm Position of object, u = - 25cm Focal length of the lens, f = 10 cm Hence, position of image, v =? We know that, 1/v - 1/u = 1/f 1/v + 1/25 = 1/10 So, 1/v = 1/10 - 1/25 S0, 1/v = (5 - 2)/50 That is, 1/v = 3/50 So, v= 50/3 = 16.66 cm Thus, distance of image is 16.66 cm on the opposite side of lens. Now, magnification = v/u That is, m = 16.66/-25 = -0.66 Also, m= height of image/height of object Or, -0.66 = height of image / 5 cm Therefore, height of image = -3.3 cm The negative sign of height of image shows that an inverted image is formed. Thus, position of image = At 16.66 cm on opposite side of lens Size of image = - 3.3 cm at the opposite side of lens Nature of image – Real and inverted.... can i have ray diagram |
|