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Per two gram of charcoal, a gas is adsorbed by 0.1g and 0.2g at 10 torr and 80 torr pressure respectively. Calculate the n value in Freundlich adsorption isotherm. |
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Answer» Solution :`(x)/(m)=K.P^(1//n)(or) (X_(1))/(X_(2))=((P_(1))/(P_(2)))^(1//n)` SUBSTITUTING the values, `(0.1)/(0.2)=((10)/(80))^(1//n) (or)((1)/(2))^(1)=((1)/(2))^(3//n)` Therefore, the VALUE of n is 3. |
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