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Period of `f(x) = sin 3x cos[3x]-cos 3x sin [3x]` (where[] denotes the greatest integer function), isA. `1//6`B. `2//3`C. `5//6`D. `1//3` |
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Answer» Correct Answer - D `{x}=x-[x]` which is periodic with period 1. Now, `f(x)=sin(3x-[3x])=sin({x})` `{3x}` has period `(1)/(3)` `therefore" "f(x)"has alos period "(1)/(3)`. |
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