1.

Period of `f(x) = sin 3x cos[3x]-cos 3x sin [3x]` (where[] denotes the greatest integer function), isA. `1//6`B. `2//3`C. `5//6`D. `1//3`

Answer» Correct Answer - D
`{x}=x-[x]` which is periodic with period 1.
Now, `f(x)=sin(3x-[3x])=sin({x})`
`{3x}` has period `(1)/(3)`
`therefore" "f(x)"has alos period "(1)/(3)`.


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