1.

Periodic acid splits glucose and fructose into formaldehyde and formic acid. Ratio of moles of formic acid in glucose and fructose is

Answer»

`1:2`
`5:3`
`1:1`
`2:3`

Solution :`CHO-CHOH - CHOH - underset("Glucose")(CHOH) - CHOH - CH_(2)OH overset(5HIO_(4)) to5HCOOH + HCHO + 5HIO_(3)`
`CH_(2)OH - overset(O)overset(||)(C)- underset("FRUCTOSE")(CHOH)- CHOH - CHOH - CH_(2)OH overset(5HIO_(4))to 3HCOOH+ 2HCHO + 5HIO_(3) + CO_(2) + H_(2)O`
`therefore ` molar ratio is 5:3


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