1.

Peroxide ion (i) has five completely filled antibonding molecular orbitals (ii) is diamagnetic (iii) has bond order one (iv) is isoelectronic with neon. Which one of these is correct ?

Answer»

(iv) and (iii)
(i),(II) and (iv)
(i), (ii) and (iii)
(i) and (iv)

Solution :Peroxide ion is `O_(2)^(2-)`
Total electrons `=18`
`E.C.=sigma1s^(2)SIGMA^(**)1s^(2)SIGMA2S^(2)sigma^(**)2s^(2)sigma(p_(z))^(2)pi(2pi_(X))^(2)pi(2p_(y))^(2)pi^(**)(2p_(x))^(2)pi^(**)(2p_(y))^(2)`
`B.O.=(10-8)/(2)=1`
Options (ii) and (iii) are correct.


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