pH calculation upon dilute of strong acid solution is generally done by equating n_(H) in original solution & diluted solution.However . If strong acid solution is very dilute then H^(+) from water are also to be considered take log3.7=0.568 and answer the following questions. A 1 litres solution of pH=4(solution ofa strong acid ) is added to the 7//3 litres of water.What is the pH of resulting solution?

pH calculation upon dilute of strong acid solution is generally done b

1.	pH calculation upon dilute of strong acid solution is generally done by equating n_(H) in original solution & diluted solution.However . If strong acid solution is very dilute then H^(+) from water are also to be considered take log3.7=0.568 and answer the following questions. A 1 litres solution of pH=4(solution ofa strong acid ) is added to the 7//3 litres of water.What is the pH of resulting solution?
Answer» `4.52` `4.365` `4.4` `4.432` Solution :INITIAL `pH=4` `[H^(+)]=10^(-4)` `N_(1)V_(1)=N_(2)V_(2)rArr 10^(-4)=N_(2)xx[1+(7)/(3)]` `10^(-4)=N_(2)xx(10)/(3)rArr N_(2)=3xx10^(-5)"" gt10^(-6)` so `[H^(+)]` of WATER is not consider `[H^(+)]=3xx10^(-5)`"" so""`pH=5-log(3)`""`=5-0.48=4.52`