1.

pH of a lemon water bottle is 3 and that of orange juice is 4. Calculate the pH of final solution obtained by mixing above solutions in volume ratio of 1 : 2 respectively. (Assuming that no change in volume on mixing and no chemical reaction is taking place) [Given : log_(10)2 =0.30]

Answer»


Solution :`V xx 10^(-3) + 2V xx 10^(-4) = 3V xx [H^(+)]`
`[H^(+)] = (10^(-3) + 2 xx 10^(-4))/(3)= 4 xx 10^(-4)`
`PH= 4- LOG 4= 4- 6= 3.40`


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