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pH of a neutral solution is equal to 7. Prove it. |
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Answer» Solution :(i) In the neutral solution the CONCENTRATIONS of `[H_3O^+]` as well as `[OH-]` are EQUAL to `1 TIMES 10^-7M` at `25^@C` (ii) The pH of a neutral solution can be calculated by substituting this `[H_3O^+]` concentration in the expression. `pH=-log_10[H_3O^+]` `=-log_10[1 times 10^-7]` `=-(-7)log""10/10=+7(1)=7` (III) pH=7 for a neutral solution. |
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