pH of a solution is 5.5 at 25^(@)C. Calculate its [OH^(-)] – InterviewSolution

1.	pH of a solution is 5.5 at 25^(@)C. Calculate its [OH^(-)]
Answer» SOLUTION :`pH+POH=14.0` `THEREFORE pOH=14.0-pH` `=14.0 -5.5 =8.50` `pOH=8.5""therefore "ANTILOG" [-pOH]` `therefore [OH^-]= "antilog" [-8.5]=3.2xx10^-9 M`.

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