1.

pH of the solution in the anode compartment of the following cell at 25^@C is x when Eced E_("cell")-E_("cell")^(@)=0.0591V. underset("1 atm")(PT (H_(2))|pH=Xx|| Ni^(2+)(M)|Ni Find the value of x.

Answer»


Solution :`NI^(2+) +H_(2) to Ni+2H^(-1)`
`K=([H^(+)]^(2))/([Ni^(2+)])=[H^(+)]^(2)`
`E_("CELL")-E_("cell")^(@)=0.0591 XX pH`
pH=1


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