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फाइंड द कॉस्ट ऑफ फेंसिंग और ए ट्रायंगुलर फील्ड ऑफ लेंथ 322 मीटर एंड ब्रेथ टू 80 मीटर एट द रेट ऑफ रुपीस 32 पॉइंट 50 मीटर |
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Answer» -step explanation:ANSWERDimension of triangle field ⇒120m,80m,50m⇒ perimeter = 120 + 80 + 50=250mArea = 125(125−120)(125−80)125−50 = 125×5×45×75 = 25×5×5×9×5×5×15 =5×5×3×5 15 =375 15 =375(3.88)=1455m 2 cost of fencing = 250−3[perimeter of Remaining fence] = 247 Total cost ⇒247m×Rs20/m=Rs4940.as the rate are reduced by 25 %∴ new lets is [20−20× 10025 ]⇒20−5=15%Rs[4950−4950× 10025 ]⇒4950(1− 41 )4950× 43 Final cost ⇒Rs3712.5 |
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