1.

phi(x) = f(x)g(x) and f'(x)g'(x) = k, then (2k)/(f(x)g(x)) =

Answer»

`(PHI''(X))/(phi(x)) - (F''(x))/(f(x)) - (g''(x))/(g(x))`
`(phi''(x))/(phi(x)) + (f''(x))/(f(x)) + (g''(x))/(g(x))`
`(phi''(x))/(phi(x)) + (f''(x))/(f(x)) - (g''(x))/(g(x))`
`(phi''(x))/(phi(x)) - (f''(x))/(f(x)) + (g''(x))/(g(x))`

Answer :B


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