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फलन ` x^(n)/(log_(e^(x)))` का x के साक्षेप अवकल गुणांक ज्ञात कीजिए । |
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Answer» `d/(dx) { (x^(n))/(log_(e)x}}= ( log_(e)xd/(dx)x^(n) - x^(n) d/(dx) log_(e)x)/( log_(e)x)^(2)` ` = ( log_(e) x. nx^(n-1) -x^(n) . 1/x)/( log_(e)x)^(2)` ` = ( nx^(n-1) log_(e)x-x^(n-1))/( log_(e)x)^(2)` ` = ( x^(n-1) ( nlog _(e) x-1))/( log_(e)x)^(2)` |
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