1.

Phosphine (PH_(3)) decomposes to produce vapours of phosphorus and H_(2) gas. What will be the change in volume when 100mL of phosphine is decomposed?

Answer»

`+50mL`
`500mL`
`+75ML`
`-500mL`

Solution :`4PH_(3)(g)rarrP_(4)(g)+6H_(@)(g)`
`4mLrarr1mL 6mL`
`100mLrarr(100)/(4) (6)/(4)XX100`
`100mAL rarr25mL 150mL`
VOLUME INCREASES by 75 mL.


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