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Phosphorous pentachloride when heated in a sealed tube at `700 K` it undergoes decomposition as `PCl_(5)(g) hArr PCl_(3)(g)+Cl_(2)(g), K_(p)=38` atm Vapour density of the mixture is `74.25`. Equilibrium constant `K_(c)` for the reaction will beA. `0.66 M`B. `0.56 M`C. `0.46 M`D. `0.36 M` |
Answer» Correct Answer - A `K_(p)=K_(c)(RT)^(Deltan), Deltan=3-1=2` `:. K_(p)=K_(c)(RT)^(2)` or `K_(c)=K_(p)/((RT)^(2))=38/((8.314xx700)^(2))` |
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