1.

Phosphorus pentachloride dissociates as follows in a closed vesselmPCl_(5)(g)hArr PCl_(3)(g)+Cl_(2)(g).If total pressure at equilibrium of the reaction mixture is P and degree of dissociation of PCl_(5) is x, the partial pressure of PCl_(3) will be :

Answer»

`((2x)/(1-X))P`
`((x)/(x-1))P`
`((x)/(1-x))P`
`((x)/(1+x))P`

SOLUTION :`{:(,PCl_(5),hArr,PCl_(3),+,Cl_(2)),("At equilibrium",1-x,,x,,x):}`
Total moles `=1-x+x+x=1+x`
PARTIAL pressure of `PCl_(3)=((x)/(1+x))P`.


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